n^2-n-0.2=0

Solution for n^2-n-0.2=0 equation:

n^2-n-0.2=0

We add all the numbers together, and all the variables

n^2-1n-0.2=0

a = 1; b = -1; c = -0.2;
Δ = b2-4ac
Δ = -12-4·1·(-0.2)
Δ = 1.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1.8}}{2*1}=\frac{1-\sqrt{1.8}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1.8}}{2*1}=\frac{1+\sqrt{1.8}}{2}
$